1. Point E (0, -28.262) is the center for Arc{AJB} with Radius 424.768. So the equation for Arc{AJB} is:
x² + ( y + 28.262 )² = 424.768² or x² + ( y + 28.262 )² = 180427.8538
2. Point H (75.509, 0) is the center for Arc{AID} with Radius 344.143. So the equation for Arc{AID} is:
( x - 75.509)² + y² = (344.143)² or ( x - 75.509)² + y² = 118434.4045
3. Point A is the intersection of Arc{AJB} and Arc{AID} and Points E, H and A are collinear. This implies that the radial segment of Arc{AJB} and the radial segment of Arc{AID} share Segment{HA} in common.
4. Therefore, the equation of Line Segment{EHA} , which is determined by Point E (0, -28.262) and Point H (75.509, 0) would be helpful in finding coordinates for Point A.
5. Show your method and work for writing the equation for Line Segment{EHA}. 6. Show your method and work for finding coordinates for Point A.
7. Show your method and work for finding coordinates for Point I. 8. Show your method and work for finding coordinates for an x = 400 first coordinate.
9. Show your method and work for finding coordinates for an x = 300 first coordinate. 10. Show your method and work for finding coordinates for an x = 200 first coordinate. 11. Show your method and work for finding coordinates for an x = 100 first coordinate. 12. Show your method and work for finding coordinates for Point J. 13. Plot these seven points and label them.
14. Plot corresponding points in the other three quadrants using symmetry and label them.
14. Draw smooth arcs through the four sets of points using a compass.
16. Follow steps 1 through 15 to plot points and draw the arcs for the inner oval.
17. Show that the tangent line at Point A for Arc{AJB} is collinear with the tangent line at Point A for Arc{AID} by:
a) a geometry demonstration
and by
b) algebra methods.
17. Why was Busch Stadium designed with these arcs?
Busch Stadium Math Problem Statement Page or
See our Pharmacokinetics mathematical models.
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